(4-2x)/(6x^2)=1

Solution for (4-2x)/(6x^2)=1 equation:

(4-2x)/(6x^2)=1

We move all terms to the left:

(4-2x)/(6x^2)-(1)=0


Domain of the equation: 6x^2!=0

x^2!=0/6

x^2!=√0

x!=0

x∈R


We add all the numbers together, and all the variables

(-2x+4)/6x^2-1=0

We multiply all the terms by the denominator


(-2x+4)-1*6x^2=0

Wy multiply elements

-6x^2+(-2x+4)=0

We get rid of parentheses

-6x^2-2x+4=0

a = -6; b = -2; c = +4;
Δ = b2-4ac
Δ = -22-4·(-6)·4
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10}{2*-6}=\frac{-8}{-12}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10}{2*-6}=\frac{12}{-12}
=-1
$